In this second section of the mechanical properties

of materials, we will discuss a very important concept called Tensors because so far we know

about this scalars and vectors. For example, when you talk about any simple numerical counting

of a system you talk about the kind of systems which are scalars. But when you talk about

something in the sense of direction let us say force for example then you talk about

it in terms of a vector. But when you talk about stress, so we actually

refer to stress not like only one direction associated with it, but if you consider for

example, for a 3 dimensional space then you have you know something like 9 components

of stress. So for this kind of a situation we need a kind of a more generic abstract

way of describing the system and that will be in terms of tensors. So that is what we will be doing for both

stresses as well as for strain. So this is kind of a generalization first of all on scalars

and vectors. Now, how do we define the tensor for say stresses and strains before we say

that, we can also show that how scalars and vectors could be special case of tensors of

certain ranks. The rank of a tensor is defined by the number of directions or dimensions

of the array that is required to describe it.

So suppose, we are talking of an N dimensional space and we are talking of a tensor with

R direction or rank R. Then it can be represented by C component such that N to the power R

equals to C. Now let us try to use this in terms of our day to day experience. Suppose

we talk of a scalar quantity, that means say how many pens you ask me, how many pens do

I have in my pocket? So suppose if I have one pen in my pocket,

then this is a scalar quantity and this scalar quantity can be considered to be a tensor

of rank 0 in a 3 dimensional space. In other words, N is here 3, R is here 0 and hence

3 to the power 0 that is only 1 component without any sense of direction, the number

of pens that is only the number itself that is a scalar quantity.

Now suppose, we talk about that how we do move from a position ‘A’ and to a position

‘B’, so now I do not only need the distance to cover, but also I need to say that which

direction I will be covering. So for example, you have to go this way and this way, the

combination of directions in order to reach this location. So if you had this kind of

a sense of direction that means you have a magnitude as well as the direction that is

associated. So it is 3 to the power 1, now in a 3 dimensional

space that means you need 3 components and no wonder that any vector in a three-dimensional

space you always denote it with respect to 3 unit vectors if you remember i, j and k,

so that you can actually say that this distance ‘D’ is nothing but something like x i

y j and z k. So that is how you define the vector in terms of the distance, velocities,

etc. There are many such thing where this you know

first rank of tensor is important. When we will talk about stress, the stress is actually

something which is a up rank 2, so it is a tensor of rank 2 which is also known as a

dyad. So that means here you need a magnitude as well as 2 directions every time. That means

it is 3 square or in other words, 9 components are needed in order to define the stress at

a point. So that is why I told you earlier that just

a very simple generalization of a stress as a force per unit area does not really make

sense because which area are we talking about. Now you have a much better definition of stress

that suppose you consider a point and you consider a cube all around this point that

is what we are showing here right, a cube all around this point and on that cube, so

you have various surfaces on the cube. And if you look at it that you need actually

you know 3 normal components, and 6 shear components. So Sigma xx, Sigma yy, Sigma zz,

are the 3 normal components and rest 6 shear components. Why we will need 6 here because

there are some shears like Sigma xy and Sigma yx which are actually say. Shear and complementary

shears are there, so you need 3 normal and the 6, total unique 9 components, in order

to define the stress at a point. And that is a tensor of rank 2 that is what

is also known as a dyad. So that just like stress is a tensor a dyad of you know that

is of rank 2 tensor. Similarly, strain is also exactly the same way tensor of rank 2.

So you need you know two rank 2 tensors to define the stress and the strain. Naturally,

you know if you are talking about modulus of elasticity, then actually you need a rank

4 for in order to define the relationship between the 2 dyads. Now there is something

more, so it is about the stress the other interesting thing is the Poisson’s ratio. This refers to that when I am actually extending

a material; let us just take this example that you are extending a material in one direction.

Suppose we are taking the material like a dog bone shape, in a universal testing machine

and I am applying tensile force. This is a rubber sample and you can see how the thickness

is reducing in the other direction. So this being a rubber imagine here, which

has a Poisson’s ratio close to 0.5, this shows beautifully that how it is narrowing

down in the direction perpendicular to the application of the force. So this nature of

a material is actually depicted by what we call the Poisson’s ratio of the materials.

So that is the Poisson’s ratio which is the ratio of the lateral strain to the tensile

strain. Now if a material does not exhibit this behavior,

there are some materials which does not exhibit this behavior for example, a cork of a bottle,

they generally neither expand you know in terms of when you are compressing it, nor

the other way round. So they have Poisson’s ratio which is close to 0. In fact, cork’s

Poisson’s ratio is nearly close to 0. Most of the other materials in the day to

day experience that we use for example, the metals, they have Poisson’s ratio between

0.25 to 0.3, etc., concrete has a Poisson’s ratio of 0.2 and rubber has a Poisson’s

ratio of as I have just now shown you that has a Poisson’s ratio close to 0.5. Can

a material have a negative Poisson’s ratio? That means when we are actually contracting

the material or expanding the materials let us say just like that rubber experience when

you are expanding the material, instead of contracting can it expand on the other direction?

Yes, in certain cases it can. Let me just show it to you through an example. Now, this

is actually a re-entrant honeycomb structure. This is a auxetic structure, so in this auxetic

structure if you look at it that it is the each of the honeycombs instead of the honeycomb

with a positive angle, they are having a negative angle, each one of them. And this is what

happens in such a case? Suppose, now I am trying to expand the material, so I am expanding

it in this direction. You see that the other direction, that is in the perpendicular direction

instead of contracting it is actually expanding. The more these re-entrant angles are actually

unfolding, it is expanding more and more. And the other way when I am compressing, you

can see other direction instead of expanding, it is also getting contracted in the other

direction. So expansion is creating expansion, compression is creating compression that is

the beauty of an auxetic structure which is having a negative Poisson’s ratio.

So we have talked about you know various types of Poisson’s ratio. And that definitely

is a very important consideration material property consideration, when we are actually

selecting a material. Now we also have talked about stress and strain, the stress and strain

are related by something which is known as Hooke’s law. So there are of course the Hooke’s laws

which actually can be considered as a relationship between a single stress factor and a single

strain or in a generic sense between stress tensor and a strain tensor. So in that case

if I consider the relationship to be a matrix relationship that means Sigma ij, equals to

E ijkl with epsilon of kl. So that is a most generic Hooke’s law. So

basically Hooke’s law is something which is relating between the stress and strain.

And each stress and strain component you know within a linear elastic domain is generally

found out to be a having a proportionality that means you know, if you increase the stress

2 times, the strain also will increase 2 times, so there is a sense of proportionality that

will that will be there between the two. So that is you know the simplest form of the

Hooke’s law which we also refer that if we do it for a component, then this actually

the ‘E’ becomes what we say as Young’s modulus named after most famous physicist

and physician Sir Thomas Young who had past you know made very important notes on and

elastic behavior of materials. Now, the way a normal stress component is

proportional to strain component and related by Young’s modulus. Similarly, if you have

a shear stress component, that will be proportional to shear strain and there the modulus of elasticity

is referred as shear modulus or ‘G’ and if you remember the case of that hydrostatic

pressure case, there actually it is not happening the change in a direction, but in terms of

a volume change. So you consider it for any fluidic case, so

that is why the negative sign is actually introduced here because the positive pressure

causes shrinkage of volume. So you know here you get the volume change as the volumetric

strain and that is related with the hydrostatic pressure and hence the modulus here is known

as the Bulk modulus, so we have 3 different modulus.

The elastic modulus in the first case it is Young’s modulus, Shear modulus and Bulk

modulus. All 3 moduli however have the same unit in terms of the unit of the stress because

the strain is unit less, so it has the same unit as the unit of the stress. So that is

about the Hooke’s law now and which correlates between stress and the strain and you can

get actually the elastic modulus of the system. The point is that this elastic modulus varies

and this is a measure of actually the stiffness of the system. The way you know very easily

I worked the rubber sample, with a steel sample if you give me; I may not be able to work

so easily, so it has a higher stiffness that means a higher modulus of elasticity. Now

this is a depicted in a beautiful chart from actually Ashby and Jones and that gives the

elastic modulus for different groups of types of materials. For example, if you consider ceramics, they

have generally a very high elastic modulus like diamond and then they may have some you

know some of the things which may have lower modulus of elasticity something like say for

example the glasses or the ice or the graphite, the cement, they may have somewhat lower modulus

of elasticity, but in general ceramics have reasonably high modulus of elasticity.

If you look at the metals, there are some metal which shows quite high modulus of elasticity

for example, tungsten is one of them, chromium is another of them no matter that is why for

the making the super alloy, these kind of materials are used because they deform much

less with the same application of force. And then there is the Iron and steel is here for

example, 200 Giga Pascal. And then much softer ones are for example,

aluminum or zinc or tin, magnesium, they are much softer in terms of the metals. Now if

you look at the polymers, you can see that there is nothing here that means the polymers

are a degree you know several orders of magnitude lower in terms of the stiffness. And there

you know something like that is why I told you that about 2 Giga Pascal is something

maximum that we generally observe. And there in the higher range you get something

like Poly methyl methacrylate, polystyrene, nylon, etc. And those which are very low are

something like thing like foamed polymers, PVCs, rubbers, etc., they show a very low

modulus of elasticity or in other words, the compliance is very high in such materials.

Then if you look at the composites, composites you know the natural composites are generally

softer, something like woods, etc. But the manmade synthetic composites actually have

modulus of elasticity which is comparably the metals, CFRPs, fiberglass’s, etc. So

that is why, composites are replacing the metals you know wherever the high stiffness

is required. So that is kind of a comparison chart which you can you not keep in your mind. In terms of the absolute values here, you

know ones again I have given 3 values we have given from Callister here and just for reference

for example, if you consider aluminum approximately 70 Giga Pascal modulus of elasticity, Shear

modulus is approximately 25 and Poisson’s ratio is approximately 0.3.

So a again in this list you would see that a high modulus of elasticity you are finding

in something like tungsten, and the shear modulus is also high in that same range, but

shear modulus is usually always lower in comparison to the you know Young’s modulus of the system.

What does it mean? It means that you know you can actually shear the material or twist

material, deform the material in the shearing mode much easily in instead of actually elongating

or compressing the material. And the Poisson’s ratio you can see is not

really varying is more or less in the range of something like 0.3 around that range, for

most of the metals. So this is just for a comparison of these properties in various

metals. Now, how we measure this property. In order to measure this property, we use

a tensile testing system in a machine a which is known as actually Universal Testing Machine

in which we find our properties like for example Ultimate Tensile Strength, yield strength,

Percentage elongation, Young’s modulus of elasticity, etc.

So I have just not shown you that in a UTM machine how we are you know we can deform

the rubber specimen, the same specimen that I have shown you can be used in this case.

Universal testing machine is a beautiful machine where you can actually load a sample in various

ways tension, compression, Shear, not only that the loading can be made dynamic loading

and which can include things like fatigue, etc.

So that is how we generally carry out this universal testing in a machine the tensile

testing. Now if you carry out such testing of a ductile metal, how would you find out

the stress strain diagram? And that is the engineering stress strain diagram of the material,

how do you usually see with the strain diagram. If you look at it that the stress strain diagram

shows certain features. But please keep in mind that this is called a ductile metal.

So you will see that there is an initial region where you know the material if you actually

unload the material, it will come back to the same point itself, that is known as the

elastic limit, that is the maximum stress that withstand without any measurable permanent

strain after unloading. Now, in the elastic limit of course there

are 2 regions, in one region after some region it is actually perfectly linear and beyond

that it is slightly nonlinear, but still if you release in the nonlinear region, it will

come back to its original position that is, what is the deforms the elastic limit. Now,

then the point comes here that is the Yield strength point. Beyond the yield strength

point, if you actually deform the material, then it will start to deform plastically.

What it means is that beyond that point if you actually start to unload, there will be

some amount of deformation which will always remain into the system. And that is why the

yield strength position is very important because says the onset of actually plastic

deformation in the system. So as I am increasing the load, I am going beyond the yield strength

level and I am actually watching the uniform plastic deformation.

Now, if I increase the load further what is going to happen is something like a necking

phenomenon that would start to happen and then the material will go in the fracture,

so that is what generally you know happens for a ductile material. So, in that beyond

that making point what you get is non uniform plastic deformation, so the plastic in itself

can be divided into 2 parts. One is the when it is uniform plastic deformation that is

the first one. And then there is non-uniform plastic deformation

till failure. So that is what we will find into the system. And what is the point that

is important for us is that up to the necking you know we get actually the Ultimate Tensile

Strength, so that is the maximum load divided by original cross sectional area of the system

that gives the Ultimate Tensile Strength, beyond that you would not expect strength

of a material because beyond that if you take the force, it is actually going to take us

towards the fracture. That is why Ultimate Tensile Strength plays

a very important role in terms of the product design. And also the other 2 important factors

are that what is the Percentage elongation that is the you know ratio of the difference

of final to initial length change over the initial length and similarly for the area.

So that actually tells us that how compliant is the material. So this is a typical stress

strain curve for a ductile material. How will it look like a brittle material,

I can just you know very in a very small qualitative manner we can draw it here that suppose this

stress is denoted by Sigma and strain by Epsilon, so if I draw the Sigma Epsilon, for a brittle

material is just one single line and maybe some point of nonlinearity, but that is it

and then it stops to phase that means it will not show any plastic strain, any plastic deformation

that is generally happens in terms of the brittle material.

The other important point here is that generally the Yield strength, if you do not find a very

sharp point where this you know this is happening, we consider approximately these 0.002 level

between the 2 percent strain level we will find out that where it is intersecting and

that point is defined as the Yield Strength level because that is generally the strain

level which it can take in general in metals without any permanent deformation.

But this is very specific to the metals for the things like elastomers or rubbers; this

can become something like 5 percent to 10 percent, so depending on the material this

position may change. Now then if we actually consider however the true stress strain curve

that means if we consider that the area is actually changing. If you look at it that as you are deforming

this area is actually changing, this area is becoming smaller and smaller, and the neck

formation is happening, so the area is changing. And if you consider that actually area, you

will see that it is not actually the stress strain curve, it is not dropping, but it is

actually increasing, height is increasing because even if the force you are increasing,

the area is actually decreasing at a very rapid rate so that is why the true stress

actually is increasing at a very rapid rate. Now in the uniform plastic deformation, the

stress strain relationship is actually governed by a power law which is like Sigma T is K

times Epsilon T to the power n, where this n is 0 for perfectly plastic solid, n is 1

for elastic solid. For most metals it will be in the plastic region between 0.1 to 0.5,

so that is how it will behave you know in the true stress strain curve which will generally

you know overlook actually, will only look at the stress strain curve that comes up in

the UTM machine. So the true stress strain curve actually true

stress is denoted by this relationship which is something like the Sigma T as Sigma times

1 plus Epsilon and the true strain Epsilon T is the natural logarithm of 1 plus Epsilon.

And the relationship between engineering strain and true strain is governed by this relationship.

So this is what you can just very simply mathematically you can actually obtain this relationship. Now the other point is that the material based

on the stress strain relationships are actually divided into sub categories like the homogeneous

materials for which the properties are actually independent of where I am measuring the property

that means, here you get a property and here you get a property, all the directions if

you look at it you are going to find the same modulus of elasticity, but it varies from

direction to direction. In one direction it is E1, in another direction

it is E2, so that is what is a homogeneous material where at different points you get

the same pattern of modulus of elasticity. For isotropic, it is actually direction independent

at a particular point if you consider, you get E1 in all the directions. But if it is

not homogeneous, then at a different point you get E2 in all the directions and E1 and

E2 are not the same, they are not the same. If they are same, then they will become homogeneous

and isotropic material. And if we consider an Orthotropic material, in that case it is

slightly different in that case we will see that at different points it is homogeneous,

but the modulus of elasticity varies in different directions in the sense it varies in 3 different

mutually orthogonal directions that will be E1, E2 and E3 and this is called General orthotropic

material. And for Specially orthotropic material you

may disregard one of them and it only varies in 1 set that means something like E2 and

E3 will vary, but E1 will remain the same, so that is what happen for Specially orthotropic

material. This is typically a case like you consider a laminated composite, then each

lamina which is very thin in one direction are actually considered to be specially orthotropic

material, so that is a very special case of a general orthotropic material. Now, the relationship, the elastic constants

are actually related with each other by the relationships which is shown here that E is

related to G and G is related to K. And hence if you know actually for a linearly elastic

isotropic and homogeneous material, you need only 2 elastic constants and then the other

2 that means we have you know these 4, K, Nu, E and G. Out of them, any 2 if you give

me I should be able to derive the other 2 provided that the material is linearly elastic,

isotropic and homogeneous material. And in case of anisotropic material, there

are 21 independent elastic constants, so it is a much higher you know in terms of the

variation. And if it is orthotropic material, then it has 9 independent elastic constants

that will come into the picture. So naturally, the tailoring is much more for an orthotropic

material. Now that is the relationship you know in terms of the actually orthotropic

and anisotropic material. So, that is about the stress strain relationship,

there are some other mechanical properties which are also important, one of them is ductility,

are already talked about it that you know it is the how much you know is the capacity

of how much you can draw a material under the tensile stress and that is very important

and there is something that you will also see in terms of ductility which is known as

the ductile failure, ductile sign of the neck formation of the system and the brittleness

of a system. So the difference between a brittle and a

ductile system I have already drawn the stress strain curve for a brittle system and a ductile

system is that precisely this ray the act you know the presence of this plastic strain

that is there for a ductile material. Now, that is absent for a brittle material. So

that is very important point that we have to keep in our mind while comparing between

various material properties. Now the other important point here is actually

the resilience of a material, which is the capacity of a material to absorb the energy

elastically, so it is in the elastic domain when it is deformed elastically you know how

much of energy it can absorb. And if you consider the stress strain diagram, and if you consider

the area under the stress strain diagram, you can actually find out that this is something

like you know Sigma Y square over 2 E in a kind of an approximate measure.

And that is so that means if you know what is the Yield Stress and if you know what the

modulus of elasticity is, you can actually compute that what is the resilience of the

material in terms of modulus of resilience and how much of energy the material can absorb,

which is very important in applications like spring type of applications. So the resilience

is another important mechanical property. The last important property in this direction

is the toughness. Toughness is also the area under the stress

strain curve, just like the earlier case, but here you are considering the plastic region

also. The earlier you were confining yourself with the elastic region, now you are considering

the plastic region also. In fact, the test that is very much important towards this direction

are actually Izod and Charpy impact tests. So this is an Izod impact test where actually

support the sample from one position here the support is here put and you are hitting

it through a pendulum and if there is no sample then it can go to a particular distance, if

there is a sample then there is some energy is actually taken by it, so it cannot go you

know up to that distance, so you take the ratio of the two, return ratio we call it.

And then that gives a measure of how much of energy is actually absorbed by the material

and which is the measure of the toughness of the material. Similarly, there is another very similar test

actually which is known as the Charpy test. Now the difference between the 2 tests, the

Izod test and the Charpy is that in the Izod test you have you have for example if I go

to the last case, you have the crack which is you make a notch actually and the notch

actually faces the hammer, so the hammer faces the notch.

So in Charpy, is you can see on the other hand the notch is on the opposite side of

the hammer, that is one of the difference between the two and also in case of a Charpy

test, you are supporting the material at two places instead of at one location. But both

of them are very good tests which can measure that how much of energy a material can absorb

and that means how tough the material is. And that actually means that you know how

much the impact strength that is there in the material is. So here is some kind of a comparison from

the Ashby’s table and as you can see here, if you look at it very closely that the metals

are topping in the list actually because they can absorb quite a good amount of impact energy.

And in fact plastics even though they deform more, they cannot absorb that much of energy,

brittle materials of course are the worst here. So that is what is in terms of the 3 different

you know groups of materials. Then composites are somewhere in between. Now, the factors

that are important in terms of the impact energy is that for a given material you know

the impact energy will decrease if the Yield strength is increased, so that is generally

found in the material. And the notch serves as a stress concentration

zone, so some materials are more sensitive to notches and the most of the impact energy

is actually absorbed during the plastic deformation of the material. Also, temperature and ductility

plays a very important role on it. So this is where we are going to close this lecture

and in the next lecture we will talk about some of few more mechanical properties that

is, the hardness of the system, the creep of the system and the damping, thank you. Keywords- Tensors, Hooke’s law, auxetic, poisson

ratio, Tensile testing, Engineering & True Stress-strain curves, brittleness, ductility,

resilience, toughness, impact testing, izod, charpy

## 3 Comments

## Zulqarnain Chaughtai

very helpful

## prabhat kumar

good lecture

## Badal Kumar

Too excellent