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Now I see how peptide bonds can form. Excellent!
Why is this video uploaded twice?
Under 301 club
I thhink that the carbone 4 in the fructose molecule is missing a hudrogen
@Khan Academy In a division problem or any kind of problem can I for instance directly dived 50.50cm^3 by 15.0cm^2 or would i have to convert one in order to do this problem
Alejandro, In the example you give you have a two scalars, the numbers 50.5 and 15, and two sets of units, the cm^3 and the cm^2. In this case you've got no big problems, because numbers divide into numbers and c^3/cm^2 is simply cm (or cm^1 if you like). So you've divided a volumve, 50.5 cm^3 by an area, the 15 cm^2, and naturally you ge a distance, 3.36666… cm. If you think of this in physical terms, a volume divided by an area might be a question about "how high is a tower of something if you know the area of the base?" Best, -dlj.
These videos are incredibly informative for me. For whatever reason the textbook would never be enough. Props to Khan Academy
how can both of them be carboxyl group
u said amino 'acid' and then u said that its a base???
Thank you ^_^
Too much on the board to follow, sorry
I've been looking everywhere for visual explanation of the functional groups, and no one does it better than you Sal! Thank you so much!
So bad, what a anarchist explanation !!
Mr Khan literally teaching the world
Helped me out a lot!!
life saver. got a bio midterm tomorrow
Anyone from CBSE class 10
You are amazing. I always find myself fascinated by your educating ways.
You forgot to mention the sub groups in carbonyl (aldehyde and ketone)
you pronounced carbonyl wrong
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