@Khan Academy In a division problem or any kind of problem can I for instance directly dived 50.50cm^3 by 15.0cm^2 or would i have to convert one in order to do this problem

In the example you give you have a two scalars, the numbers 50.5 and 15, and two sets of units, the cm^3 and the cm^2.

In this case you've got no big problems, because numbers divide into numbers and c^3/cm^2 is simply cm (or cm^1 if you like). So you've divided a volumve, 50.5 cm^3 by an area, the 15 cm^2, and naturally you ge a distance, 3.36666… cm.

If you think of this in physical terms, a volume divided by an area might be a question about "how high is a tower of something if you know the area of the base?"

## 27 Comments

## Anders Clark

First

## James Craver

Now I see how peptide bonds can form. Excellent!

## William Smith

Why is this video uploaded twice?

## Renny Hoang

Under 301 club

## Mouad Alami

I thhink that the carbone 4 in the fructose molecule is missing a hudrogen

## Chetuya Joseph

Thanks Sal.

## AVO

@Khan Academy In a division problem or any kind of problem can I for instance directly dived 50.50cm^3 by 15.0cm^2 or would i have to convert one in order to do this problem

## David Lloyd-Jones

Alejandro,

In the example you give you have a two scalars, the numbers 50.5 and 15, and two sets of units, the cm^3 and the cm^2.

In this case you've got no big problems, because numbers divide into numbers and c^3/cm^2 is simply cm (or cm^1 if you like). So you've divided a volumve, 50.5 cm^3 by an area, the 15 cm^2, and naturally you ge a distance, 3.36666… cm.

If you think of this in physical terms, a volume divided by an area might be a question about "how high is a tower of something if you know the area of the base?"

Best,

-dlj.

## Patrick Garcia

These videos are incredibly informative for me. For whatever reason the textbook would never be enough. Props to Khan Academy

## Correctrix

"Carboneeel"? :p

## Arpita Saxena

how can both of them be carboxyl group

## Prabhanshu Katiyar

u said amino 'acid' and then u said that its a base???

## Tanisha Goel

Thank you ^_^

## sai thej

usefullllll

## tracy scanlon

Too much on the board to follow, sorry

## Ruby Hagrid

I've been looking everywhere for visual explanation of the functional groups, and no one does it better than you Sal! Thank you so much!

## zayn nioding

voice??

## belal kamel

So bad, what a anarchist explanation !!

## Cristina Lingvay

Mr Khan literally teaching the world

## Zachary

Helped me out a lot!!

## Cataleya Sazo

life saver. got a bio midterm tomorrow

## Jijo Jose

thanks

## Prajwall Narayana

Anyone from CBSE class 10

## Jeff Willis

Outstanding

## Kristin Ford

You are amazing. I always find myself fascinated by your educating ways.

## DKiNG LJ

You forgot to mention the sub groups in carbonyl (aldehyde and ketone)

## yahvonne

you pronounced carbonyl wrong